Message from @celticflame
Discord ID: 509923151463972895
@Wood-Ape - OK/MN True.
@VinceChaos got it thanks
Richard Spencer should speak at the next IE conference
@ThisIsChris f""(x) + f"'(x) = 0?
Haha
I love my blue collar humble roots
@Jacob Should he be before or after Kanye?
@Nemets Good lord. Who was that? The Order?
he forages mushrooms
Wow Richard has nothing, not even his wife and child.
@Sam Anderson We can have Kanye go first, and then they'll do a panel together
@Nemets Ahhh
Richard has his leftist gf
Richards brand is tarnished at this point, the movement needs to ignore him
@ThisIsChris Your original question asked me to find f(x) from f"(x) + f(x) = 0. How did you get that answer?
And she is not even that hot
@Nemets Gay Wiggas from Outer Space
@John Riggs So he's in the hole.
@Wood-Ape - OK/MN Don't @ yourself, it scares me.
In the hole?
@ThisIsChris As far as I know, you weren't asking for anything in regards to a or b.
PAtrick Casey joins Doki Doki Literature Club.
@Rabbidsith one way is if just you happen to know that a\*sin(x) and b\*cos(x) when differentiated twice are the negative of themselves.
Reading Identity Rising now
The next IE conference will include a panel on Black Conservatism and the Faustian Spirit
@Jacob Brittanny Venti speaks on the Goblin Realm
@Rabbidsith if you're asking how to know without happening to know that fact, then if you assume there is a power series solution then you can find a recurrence relation for the coefficients of a solution.
just read Endurance by Alfred Lansing...what a tale
@ThisIsChris Well yes. That is true. However, I could also just argue that both f"(x) and f(x) are equal to 0.
Yes
@Jacob "Based or Redpilled? Must it be Both?"
Uhhh
Idk about cowboy boots.
As long as there nice looking boots
Doug Dimmadome wears boots with a suit
0 differentiated twice is still 0 so that is also a valid answer.
@Rabbidsith that's true, you would get that solution if you plug in a=0 and b=0 into a\*sin(x) + b\*cos(x)