@Freiheit - CA Your going to be competing against some of the biggest corporations in the world, do you plan on wildcating? I think that's going to be your only in, get in early like some of the smaller companies did in the bakkan. it doesn't help that there is record production of oil at the moment.

I must clarify. I'm looking for an entry option. Where would someone with no experience begin to end at high pay?

It's possible to walk onto a rig as a roughneck and elevate yourself to company man position if you are very competant, adverse to high stress, can pick up technical drilling intuition, and are ok with very little social life that comes with living in remote areas and a disproportionately male population. If you can handle all that there is good money to be made.

@Brandon Ironside- ND Have you worked in the oil industry? I was under the impression the boom was dead

@John O - only as an intern for a brief period. The boom is dead for now with the current oil prices. I choose to take my career into a different engineering direction after what little exposure I did have right out of college.

there still is work though, just not boom levels

Is it $120k a year like it was a decade ago?

I'm not considering it, just wondering. I know a lot of guys who made ridiculous money back then

newer engineers aren't making that anymore, senior engineers can make 200-300k still.

my friends who did get oil engineering jobs are making 55 - 75k similar to other engineering fields just out of college

I'm talking roughnecks

41653

Oh, yea close to above number now

That sucks.

Happy Pi Day!

Any of you goys into data mining? I've been fiddling around with R a lot recently.

@Attrition in the desert

@ThisIsChris Yeah I structure a lot of unstructured data on the web for economic system research mostly.

Been getting into data science comprehensively lately, I feel like the field is about to blow up.

@Attrition in the desert definitely! What data is it that you are making available and to who?

@ThisIsChris Mostly data on commerce exchanges in SE asia. The place I'm working at now handles a lot of soft/hard currency transactions.

https://www.livescience.com/60476-jellyfish-sleep.html

That's neat. I wonder if it's simultaneously done in all areas of the animal.

Hey guys, I'm Nick, and I'm a ChemE undergraduate from NY, excited to talk with all of you

nic

*nice

@Nicholas1166 - NY roll'd

roll'd?

@Nicholas1166 - NY sorry, role'd not roll'd. I gave you the @`AE` role (academic expert) so you will be alerted when people ping @`AE` with academic questions you may be able to help with.

Ah, OK. Yeah, I'd be glad to lend a hand if I can, although I am just a junior right now

I'm graduated from a university with a degree in math

ask me math questions

if you need halp

I very well might, math is my weakest subject. Thank you for the offer.

I didn't know this sever had a role thing. Can I get a role and be alerted?

@micbwilli done!

@ThisIsChris hey do you have any good explanation on how to find isomorphisms between two polynomial factor groups?

that is an isomorphism phi: F[x]/f1(x) -> F[x]/f2(x) where F[x] is the field of polynomials with coefficients in Z_q and f1(x) and f2(x) are irreducible polynomials in F[x]

@YourFundamentalTheorum by F[x]/f1(x) do you mean a quotient group? If so, what is the group you are doing F[x] modulo with? f1 doesn't generate a group unless I am missing something

@ThisIsChris quotient field

and F[x] is a field of polynomials in x with coefficients in Z_q

@YourFundamentalTheorum thanks. How about for an element of F[x]/f1 called G, take a representative g, phi(G) = the coset of g*f2/f1 . Need to prove that the coset is independent of the choice of representative g

the last part is a given.

On the right hand side I mean g times f2 divided by f1 in the normal sense for poly nomials

F[x]/f1(x) is usually represented by all the polynomials """"less than""""" f1(x)

a lesser degree than f1(x) that is

Hm, what happens in the three cases where f2 is higher, equal, or lesser degree than f1?

assume f1 and f2 are of the same degree

otherwise you don't have the same cardinalities

which means they can't be isomorphic

the Galois fields can't be isomorphic that is

Hm I think you can actually prove it if the degrees mismatch too. Since you assume the rep g has degree strictly less than f1, then g*f2/f1 should have degree strictly less than f2

yes you can prove that

it's quite easy actually

the degrees part htat is

we know the exact # of elements in F[x]/f1(x)

it's going to be q^n

i'm assuming q is prime btw

Sure since it's irreducible. Otherwise, hm...

If a polynomial has a non-prime degree, to guarantee reducibility you need to allow complex coefficients, right?

i don't think it matters what the degree of the polynomial is

like if it's prime or not

i think what matters are the coefficients

if you don't have prime coefficients, your polynomials stop being a field

the reason why F[x] is a field is because Z_q is a field when q is prime

if q is not prime, Z_q is not a field

and therefore F[x] is not guaranteed to be a field

Why is Z_q not a field when q is, say, 4?

the very basic example is that say if you have Z_4, the polynomial "2" does not have a multiplicative inverse

Ohh

Neat

Z_4 is not a field because 2 does not have a multiplicative inverse

Yeah haha been a while

and since Z_q is a subfield of F_q[x]

yeah I've literally pullen out my abstract alg. book out today

i need some cryptography knowledge from it

i learned all of this again today 😛

That's neat. I enjoyed abstract algebra but mostly only needed the linear algebra part since then (11 years ago). Rotation groups and some other stuff relevant to geometry, but not much more. Cryptography seems interesting, we did cover RSA at some point, I only remember the main idea, that factoring is hard 😁

@ThisIsChris wellyeah, some pajeets found a way to crack RSA with you guessed it, Galois fields

Is that a recent thing?

yeah

like a year or so

it's amazing how irrelevant Abstract Algebra used to be until computers, and now it's hella important

Huh no kidding. Guess I better put 2FA on my bank accounts then

yep

idk about you, my dad make me take applied math

it was "fun" i guess, but I really want to go back to college and get a pure math degree

later

😛

pure math is so much more fun that learning about how to earn money at google

"pure math is fun" I will never understand you types

https://giphy.com/gifs/frog-get-out-U9DiGJDKfbwGY

@Deleted User

@ThisIsChris

I'll stop there

@YourFundamentalTheorum haha I like the sigma algebra one but don't get the epic one? It's a true statement if f is 1-1 and onto. Not sure what else.

@ThisIsChris epic means an epimorphism

which is literally defined by that equation