Message from @3778

Discord ID: 802214876055076904


2021-01-22 14:48:39 UTC  

to figure this out. you could have to do SinA/a = SinB/b

2021-01-22 14:49:15 UTC  

since we are finding b, we will isolate b by cross multiplying to get SinA(b) = SinB(a) and than we divide both sides by a to get SinB by itself and the equation is SinB=(b)SinA/a

2021-01-22 14:55:40 UTC  

once we input our values we have SinB = 0.923103246

2021-01-22 14:56:09 UTC  

now we have to Isolate B and to do that we have B = inverse sin(0.923103246)

2021-01-22 14:56:45 UTC  

our angle B is 67 degrees for quardrent 1

2021-01-22 14:57:11 UTC  

to figure out quadrent 2, we simply subtract 180 from theta. this case B

2021-01-22 14:57:59 UTC  

therefore we have 2 B angles. 112 degrees and 67 degrees.

2021-01-22 14:58:18 UTC  

to find the C angle you just have to subtract 180 from angle A and angle B

2021-01-22 14:59:07 UTC  

180-59-67=54 degrees again with our other angle. 180-59-112=9 degrees

2021-01-22 14:59:17 UTC  

@bohemian52983 I took that last year and loved it, good luck and I know you'll do great!

2021-01-22 15:02:23 UTC  

next we just have to use the sine formula but SinA/a = SinC/c and cross multiply and isolate to get SinC(a)/SinA = c and keep in mind the you have to do this twice with 54 degrees and 9 degrees

2021-01-22 15:05:42 UTC  

I used 54 degrees and got a length of 12.2 9 degrees and got 2.3 which is close enough to 2.2 so the actual answer was d

2021-01-22 16:05:03 UTC  

how the hell does this work

https://cdn.discordapp.com/attachments/801170141907386408/802207206710837330/unknown.png

2021-01-22 16:05:26 UTC  

i got 7 but there was no 7

2021-01-22 16:05:58 UTC  

the last answer kills me

2021-01-22 16:06:01 UTC  

🤣

2021-01-22 16:06:13 UTC  

yeah, pretty accurate

2021-01-22 16:10:35 UTC  

I think it would first see the larger of a or b than the minimum of c and the larger of a,b

2021-01-22 16:18:46 UTC  

yeah, larger is a, so 4, then the 3 from c

2021-01-22 16:18:57 UTC  

its either 6 or 7, and ive got no idea

2021-01-22 16:35:30 UTC  

same bro

2021-01-22 17:28:30 UTC  

I see you too have been using guns as your go to controversial topic

2021-01-22 18:15:08 UTC  

There’s only 2,3,4 so I puked assume it’s 3

2021-01-22 18:17:34 UTC  

It's three

2021-01-22 18:23:48 UTC  

Yeah I thought it was weird fornit to be 7 since it looks like they are looking for the largest or smallest

2021-01-22 18:46:55 UTC  

It’s 3, but couldn’t you have copied and pasted it to whatever Java IDE you use?

2021-01-22 19:27:18 UTC  

that's cheating though, no?

2021-01-22 19:32:22 UTC  

I guess it depends on the teacher/professor. I’ve had classes where we were encouraged to use any available resources

2021-01-22 19:38:17 UTC  

idk

2021-01-22 20:11:37 UTC  

It's not cheating when are programming at your work place

2021-01-22 20:13:33 UTC  

oh well, lol

2021-01-23 00:06:32 UTC  

Would anyone be kind enough to help me out with some geometry? I need to calculate the surface area of a candle. It's mostly a simply cylinder, but it has an indent, and I want to make sure I'm calculating everything properly.

2021-01-23 00:19:12 UTC  

https://cdn.discordapp.com/attachments/801170141907386408/802331566369406986/unknown.png

2021-01-23 00:19:19 UTC  

I created this diagram.

2021-01-23 00:23:19 UTC  

**V = (𝛑1.5^2 * 4.5) - (𝛑1.25^2 * 1.25)**

2021-01-23 00:23:32 UTC  

This is the equation I came up with. Can anyone verify this?

2021-01-23 00:24:22 UTC  

(*V=Ď€r^2h* is the equation for cylinder volume.)

2021-01-23 00:41:33 UTC  

It's the volume of the red minus the volume of the green, so if your formula calculates that I'd say it's right

2021-01-23 00:43:24 UTC  

Do you know what the functions each do?

2021-01-23 00:44:09 UTC  

Thanks. That's what I did, I'm just looking for review in case someone else sees something I missed.

2021-01-23 00:44:17 UTC  

**SA = (2𝛑1.5^2 + 2𝛑1.5 * 4.5) + (2𝛑1.25*1.25)**