to figure this out. you could have to do SinA/a = SinB/b

since we are finding b, we will isolate b by cross multiplying to get SinA(b) = SinB(a) and than we divide both sides by a to get SinB by itself and the equation is SinB=(b)SinA/a

once we input our values we have SinB = 0.923103246

now we have to Isolate B and to do that we have B = inverse sin(0.923103246)

our angle B is 67 degrees for quardrent 1

to figure out quadrent 2, we simply subtract 180 from theta. this case B

therefore we have 2 B angles. 112 degrees and 67 degrees.

to find the C angle you just have to subtract 180 from angle A and angle B

180-59-67=54 degrees again with our other angle. 180-59-112=9 degrees

@bohemian52983 I took that last year and loved it, good luck and I know you'll do great!

next we just have to use the sine formula but SinA/a = SinC/c and cross multiply and isolate to get SinC(a)/SinA = c and keep in mind the you have to do this twice with 54 degrees and 9 degrees

I used 54 degrees and got a length of 12.2 9 degrees and got 2.3 which is close enough to 2.2 so the actual answer was d

how the hell does this work

i got 7 but there was no 7

the last answer kills me

🤣

yeah, pretty accurate

I think it would first see the larger of a or b than the minimum of c and the larger of a,b

yeah, larger is a, so 4, then the 3 from c

its either 6 or 7, and ive got no idea

same bro

I see you too have been using guns as your go to controversial topic

There’s only 2,3,4 so I puked assume it’s 3

It's three

Yeah I thought it was weird fornit to be 7 since it looks like they are looking for the largest or smallest

It’s 3, but couldn’t you have copied and pasted it to whatever Java IDE you use?

that's cheating though, no?

I guess it depends on the teacher/professor. I’ve had classes where we were encouraged to use any available resources

idk

It's not cheating when are programming at your work place

oh well, lol

Would anyone be kind enough to help me out with some geometry? I need to calculate the surface area of a candle. It's mostly a simply cylinder, but it has an indent, and I want to make sure I'm calculating everything properly.

I created this diagram.

**V = (𝛑1.5^2 * 4.5) - (𝛑1.25^2 * 1.25)**

This is the equation I came up with. Can anyone verify this?

(*V=πr^2h* is the equation for cylinder volume.)

It's the volume of the red minus the volume of the green, so if your formula calculates that I'd say it's right

Do you know what the functions each do?

Thanks. That's what I did, I'm just looking for review in case someone else sees something I missed.

**SA = (2𝛑1.5^2 + 2𝛑1.5 * 4.5) + (2𝛑1.25*1.25)**