the last answer kills me

🤣

yeah, pretty accurate

I think it would first see the larger of a or b than the minimum of c and the larger of a,b

yeah, larger is a, so 4, then the 3 from c

its either 6 or 7, and ive got no idea

same bro

I see you too have been using guns as your go to controversial topic

There’s only 2,3,4 so I puked assume it’s 3

It's three

Yeah I thought it was weird fornit to be 7 since it looks like they are looking for the largest or smallest

It’s 3, but couldn’t you have copied and pasted it to whatever Java IDE you use?

that's cheating though, no?

I guess it depends on the teacher/professor. I’ve had classes where we were encouraged to use any available resources

idk

It's not cheating when are programming at your work place

oh well, lol

Would anyone be kind enough to help me out with some geometry? I need to calculate the surface area of a candle. It's mostly a simply cylinder, but it has an indent, and I want to make sure I'm calculating everything properly.

I created this diagram.

**V = (𝛑1.5^2 * 4.5) - (𝛑1.25^2 * 1.25)**

This is the equation I came up with. Can anyone verify this?

(*V=πr^2h* is the equation for cylinder volume.)

It's the volume of the red minus the volume of the green, so if your formula calculates that I'd say it's right

Do you know what the functions each do?

Thanks. That's what I did, I'm just looking for review in case someone else sees something I missed.

**SA = (2𝛑1.5^2 + 2𝛑1.5 * 4.5) + (2𝛑1.25*1.25)**

I believe this is what the surface area would be?

Where'd the extra 2 come from?

Volume is surface * height yeah

Basically it calculates the surface area of the red cylinder then adds the surface area of the green cylinder's walls/sides.

Since it would be necessary to count that too.

Well the surface area their faces times their heights

*SA (of a cylinder) = 2πrh+2πr2^2*

I just reversed it.

So I did *2πr2^2 + 2πrh*.

Are you looking to find surface area or volume?

Both.

Oh cool lol. Took me a minute

**V = (𝛑1.5^2 * 4.5) - (𝛑1.25^2 * 1.25)
SA = (2𝛑1.5^2 + 2𝛑1.5 * 4.5) + (2𝛑1.25*1.25)**

These are my calculations.