Then you have (t)(.0015t+.01)=0

it's just simple algebra. moving equations on the right side all over to the left (switch the sign) so the right is now zero

I would imagine there would only be 1 solution then since it's quadratic

sorry if my shortcut is confusing 😓

Yeah, that much i get

it's also 0,0 since they have the same vertex location

okay, good. i often made tiny mistakes so it's good that you double-checked me on that

yes, kinda. that's after you set the equation to 0

ok I just factored, solved for t and got 6.66

I"m on the right track, I think I can solve this right now

ok so my final answer is 0.287, idk how f(x) even works

oh wait I forgot the square

nvm

can someone check if this is right btw

Ngl, once I got out of my algebra class I kinda forgot everything cause I need to memorize all my trig stuff.

So I can barely tell what is right and wrong here

oh all I remember from trig is the sine and cosine law

I haven't gotten there yet. I know I've learned it before though. I am only 2 days into the class rn

at least with algerbra you can verify it. with trig it's pretty hard to verify

Accurate

oh sine law is annoying but cosine law isn't bad

if you are given 2 side lengths and an angle of the missing side than you can use a calculator in 1 press

Yeah I remember that they weren't too bad. I just did them over the summer, so I should be fine.

you in hs or

Yeah, i'm taking a concurrent enrollment trug class though.

We only have 3 tests and they are 60% of the grade. Kinda scary, but we'll be fine hopefully...

But yeah I think I remember what you mean.

ooooh 60% of the grade

I didn’t do bad in trigonometry surprisingly

Like if you have angle 27° with the side across as 10 ft and the hypotenuse of x or whatever you can do sine 27 = 10/x

I just remember doing the sine and cosine law. Trig ratios. And referent angle

Is that what you mean here?

oh not soh cah toa

Oh.

It’s SineA/a = SineB/b = SineC/ c

Oh

I think I remember now.

Yeah this one was annoying as hell

that's what i got for t. i think the question ask for t, though

eh I’ll just put it will be 0.022 mm/hr at 6.667 hours just to be safe

I have trig to do in a bit, so i'll ask y'all if I have questions on it