idk if in this context is if this is where the parabolas collide with each other or not

do I factor out a t to make a linear equation?

the teacher knows that I didn't do it because idk the steps and likely she never taught me

no. you equate the two equations together (at least from my initial read through/thought process), and solve for time. the purpose is to find a time where both cultures have the same amount of cells/unit area

So put equation a at left side and equation b at the right side?

yes. just make them equal to each other (ie. both equations have the same end result)

Wow I still don’t understand

But why 2 specifically?

yea it is

Sorry, missed that message before😅

Dw don’t know to solve the final one other than perhaps graphing

because I know s(t) is basically y

Or use elimination idk

So i followed it up to this point

What i think you'd do from here is add .01 t to the other side (canceling it out on the left). Then I'd divide by t so that we have .0015t on the left and .01 on the right. Then if you divide by .0015 on either side you should get t=.01/.0015 and whatever that ends up being is an answer.

I still don't get it, maybe I should see if I can use the quadratic equation and remove the S(t)

I just did elimination and got to 0.0015 t^2 - 0.01t = 0

Which is where I got

ok I could factor a t and solve to t

Then you have (t)(.0015t+.01)=0

it's just simple algebra. moving equations on the right side all over to the left (switch the sign) so the right is now zero

I would imagine there would only be 1 solution then since it's quadratic

sorry if my shortcut is confusing 😓

Yeah, that much i get

it's also 0,0 since they have the same vertex location

okay, good. i often made tiny mistakes so it's good that you double-checked me on that

yes, kinda. that's after you set the equation to 0

ok I just factored, solved for t and got 6.66

I"m on the right track, I think I can solve this right now

ok so my final answer is 0.287, idk how f(x) even works

oh wait I forgot the square

nvm

can someone check if this is right btw

Ngl, once I got out of my algebra class I kinda forgot everything cause I need to memorize all my trig stuff.

So I can barely tell what is right and wrong here

oh all I remember from trig is the sine and cosine law

I haven't gotten there yet. I know I've learned it before though. I am only 2 days into the class rn

at least with algerbra you can verify it. with trig it's pretty hard to verify

Accurate

oh sine law is annoying but cosine law isn't bad

if you are given 2 side lengths and an angle of the missing side than you can use a calculator in 1 press