Message from @Trixxle

Discord ID: 684773538749481004


2020-03-04 14:28:45 UTC  

It's called atmospheric refraction

2020-03-04 14:30:18 UTC  

If you take the atmospheric refraction into account, 9.41 miles becomes very reasonable

2020-03-04 14:30:50 UTC  

https://cdn.discordapp.com/attachments/484516084846952451/684769831412957216/refracting.png

2020-03-04 14:31:19 UTC  

Where is the geometric horizon then in that image?

2020-03-04 14:32:31 UTC  

@Trixxle explain to me how the horizontal refraction here works

2020-03-04 14:33:12 UTC  

What do you think atmospheric conditions were from mile 0 to mile 5

2020-03-04 14:36:05 UTC  

ph well looks like they dead 😄

2020-03-04 14:38:56 UTC  

@Logrian it's where you see the ocean end?

2020-03-04 14:39:39 UTC  

im dumb tho, so can you take the image and draw in thick red crayon where that is specifically?

2020-03-04 14:39:49 UTC  

No I can't

2020-03-04 14:39:54 UTC  

I don't have perms

2020-03-04 14:40:07 UTC  

you have image perms

2020-03-04 14:40:11 UTC  

i gave them you

2020-03-04 14:41:02 UTC  

@Citizen Z the light goes up, hits the atmosphere and goes into your eyes

2020-03-04 14:41:55 UTC  

https://cdn.discordapp.com/attachments/484516084846952451/684772621929152512/IMG_20200304_144148.png

2020-03-04 14:42:00 UTC  

Right about there id say

2020-03-04 14:42:37 UTC  

so where should the horizon be if it were geometric at one foot height?

2020-03-04 14:42:43 UTC  

Thanks for the perms btw <:goose:625498032036642847>

2020-03-04 14:43:03 UTC  

I don't know, don't know enough about the image

2020-03-04 14:44:22 UTC  

Well you can work it out, its 1.225 times the square root of the observer height 🙂

2020-03-04 14:45:34 UTC  

Where does that come from? 👀

2020-03-04 14:45:42 UTC  

Never heard about that formula

2020-03-04 14:45:52 UTC  

What is the Radius of the glob model?

2020-03-04 14:46:01 UTC  

Around 6300km

2020-03-04 14:46:14 UTC  

thats where it comes from, its called geometry 😉

2020-03-04 14:46:43 UTC  

if R is that then all Horizons must be no more than 1.225 times the square root of observer height

2020-03-04 14:47:45 UTC  

one foot obseerver height put the horizon where>? Draw in crayon again, yellow this time, thanks 🙂

2020-03-04 14:48:21 UTC  

I'll do so I gtg now tho

2020-03-04 14:48:27 UTC  

ok

2020-03-04 16:56:49 UTC  
2020-03-04 16:56:56 UTC  

we

2020-03-04 16:56:58 UTC  

hi

2020-03-04 16:58:29 UTC  

a

2020-03-04 17:23:19 UTC  

Dimensional analysis tells me your formula is wrong

2020-03-04 17:23:40 UTC  

Or at least that 1.225 must have a unit

2020-03-04 17:39:02 UTC  

Ah yes, units.

2020-03-04 17:39:35 UTC  

They are a communist judeo-masonic conspiracy.

2020-03-04 17:39:43 UTC  

You heard it here first.

2020-03-04 17:57:46 UTC  

Ilks youre wrong

2020-03-04 17:58:07 UTC  

you offer nothing as a correction I see so move along

2020-03-04 18:05:05 UTC  

Youre saying that a distance is equal to the square root of a distance