No I can't

I don't have perms

you have image perms

i gave them you

@Citizen Z the light goes up, hits the atmosphere and goes into your eyes

Right about there id say

so where should the horizon be if it were geometric at one foot height?

Thanks for the perms btw <:goose:625498032036642847>

I don't know, don't know enough about the image

Well you can work it out, its 1.225 times the square root of the observer height 🙂

Where does that come from? 👀

Never heard about that formula

What is the Radius of the glob model?

Around 6300km

thats where it comes from, its called geometry 😉

if R is that then all Horizons must be no more than 1.225 times the square root of observer height

one foot obseerver height put the horizon where>? Draw in crayon again, yellow this time, thanks 🙂

I'll do so I gtg now tho

ok

@Goldstation hi man

we

hi

a

Dimensional analysis tells me your formula is wrong

Or at least that 1.225 must have a unit

Ah yes, units.

They are a communist judeo-masonic conspiracy.

You heard it here first.

Ilks youre wrong

you offer nothing as a correction I see so move along

Youre saying that a distance is equal to the square root of a distance

This is meaningless

I got to reading about Electronic polarization and wow

@Logrian was your formula for the distance of the geometric horizon?

Tell me whats the formuli then?

distance square root of height

I think the exact formula is D = √ (2hR + h²)

So for a small height D ≈ √ (2hR)=√(2R) √h

The distance is proportionnal to the square root of the height but as i said the constant have a unit

so now answer the question, at one foot whats the distance of the physical geometric horizon supposed to be?