yes there can't be negative fishy.

you can plug that formula to desmos and look at the vertex (which would give you the temp. where there is 0 fish)

alternatively, you can also convert the standard form to vertex form

So in theory i could get my .25 of a point back if i harass him enough?

ah wait shit, no

i read the formula wrong

the parabola would be upside down

so vertex is max fish

and the 0's are where there is no fish

Yeah but there cant be negative fish

Imposible

yeah, but the question asks what the temp. wherein the fish population is 0

120 would be 0 because its a real life problem no?

oh wait i see what you're saying now

Yeahhh

no. 120 degree is 120 degree 😂

it's not considered 0 degree

No im saying 120 degree is a negative amount of fish, witch is impossible so theres 0 fish

yeah

yes, so it's impossible for 120 degree to be "correct" answer

Thank you pineapple person

here is a pineapple for you

🍍

Iso what does that stand for?

my original name was isoboto 😄 people shortened it to iso

I like the pineapple one better 😢

It will always stick with you

it might make a comeback 😆 i like OffensivePineapple too, but imma see until the Offensive trend go away

Stupid taco guy

pineapple taco is da best <:TrumpSmile:720121948088041513>

Depends beef taco with pineapple sounds gross, but fish tacos with pineapple is boss

Does anyone know how to do slope form

Which one? There’s slope-intercept, point-slope, and standard

Slope= -2 (-7,13)

Slope intercept

The equation would be y = mx + b

ok ty

Anypne help with this?

Do you know how to use substitution or elimination?

Put it into slope intercept form first, and if the slopes are the same then it is parallel and if the slopes are opposite-reciprocals of each other then it is perpendicular

I forgot how to put it in slope intercept lol

wait