im wrong

derp

aka -3-5 / 2-(-4)

ok

so like grou the x and y values basically

https://lambda.sx/4gr.png

yeah you separate from both values the X and Y above and under the line

then you find the C from with that number

isnt this explained in your text book?

oh i vaguely remember this

im talking algebra II

so fucking bad at it

this is pretty basic

i failed algebra II in highschool im poretty sure

that is the slope formula

so Tervy it would be -3-5 over 2-(-4)?

ye

oh okay and that just fionds me what? k?

that gives you partial answer what you use to calculate C

and with together you get the calculation Y=K*X+C

and yes you get the K with that delta Y / delta X

was i supposed to solve the y2-y1 ove x2-x1?

cuz i did

and got -8/6

or -1 1/3

-1.3333333

easier if you dont transfer it to decimals

you are supposed to get -8/6 afaik

ok

ofc common factor 2 makes it -4/3

ok

swo now where do i go from here

then its justthen its just y=-4/3*X-C and we take your first numbers aka 5=-4/3*(-4)+C

and from that you can calculate the C by basic algrebra spinning

what is c exactly

like what is that variable for

its part of the line equation

i dont remenevbr ever learning that ugh

i think in english language the linear function uses Y=M*X+K

basically how far your line is moved from the centre

c means slope?