Message from @Alibaba
Discord ID: 254343917548470283
You provide no inherent axiom from which to ascertain any such justification be necassary.
yeah but I used pythagoras's secret trick first and multiplied after placing b(co2) on the x axis
GO TO SLEEP. FUCK. DON'T DO THIS TO YOUR BODY.
But aren't there two options available if one of the three heads is already in use?
"in use"
-_-
^
Codename Kids Next Door.
i watched that
it was ok i suppose
Number One voices Joeseph Joestar. 😉
I'll be looking forward to that answer, then.
what's this
oh q24
Probability of heads given that previous answer was heads
P(A|B) =P(A and B) /P(B)
P(A and B) = P(choose bias) * P(head from bias) = 1 * 1/2=1/2
do notifications wake Chaos?
I think I figured out a question on that math exam
I ment IQ test
And P(B) = P(choose fair and get head) + P(choose bias and get head)
Which is 3/4
So 1/2 divided by 3/4 is 2/3
Probability of getting another head is 2/3
I have no idea of how that method works
all I did was exclude the first coin
Basically it's conditional probability
unless you're supposed to put it back in
What's the chance of getting the double head given that the first side was a head
A is the probability of getting the biased coin and B is the probability of getting a head from next flip
So P(A and B) is the probability of getting the biased coin and getting a head next
hey
PC/PS4
mostly PC
I'll tag you as a PC player in that case
..Nevermind
thanks
😉