Message from @dunce

Discord ID: 254341619908739073


2016-12-02 19:51:13 UTC  

dude dyslexia is my fetish

2016-12-02 19:51:18 UTC  

send pics

2016-12-02 19:51:28 UTC  

of her fucked up spelling I mean

2016-12-02 19:54:30 UTC  

2PM

2016-12-02 19:59:22 UTC  

I think the answer to question 24 of matrix67 is 50%

2016-12-02 19:59:54 UTC  

only one I could answer @Chaos

2016-12-02 20:01:21 UTC  

You provide no inherent axiom from which to ascertain any such justification be necassary.

2016-12-02 20:01:24 UTC  

yeah but I used pythagoras's secret trick first and multiplied after placing b(co2) on the x axis

2016-12-02 20:02:05 UTC  

GO TO SLEEP. FUCK. DON'T DO THIS TO YOUR BODY.

2016-12-02 20:02:07 UTC  

But aren't there two options available if one of the three heads is already in use?

2016-12-02 20:02:19 UTC  

"in use"

2016-12-02 20:02:31 UTC  

-_-

2016-12-02 20:02:36 UTC  

^

2016-12-02 20:03:26 UTC  

Codename Kids Next Door.

2016-12-02 20:03:33 UTC  

i watched that

2016-12-02 20:03:41 UTC  

it was ok i suppose

2016-12-02 20:03:47 UTC  

Number One voices Joeseph Joestar. 😉

2016-12-02 20:05:20 UTC  

I'll be looking forward to that answer, then.

2016-12-02 20:17:36 UTC  

what's this

2016-12-02 20:19:32 UTC  

oh q24

2016-12-02 20:22:47 UTC  

Probability of heads given that previous answer was heads

2016-12-02 20:29:50 UTC  

P(A|B) =P(A and B) /P(B)

2016-12-02 20:30:21 UTC  

P(A and B) = P(choose bias) * P(head from bias) = 1 * 1/2=1/2

2016-12-02 20:31:22 UTC  

do notifications wake Chaos?

2016-12-02 20:31:49 UTC  

I think I figured out a question on that math exam

2016-12-02 20:31:55 UTC  

fuck

2016-12-02 20:31:59 UTC  

I ment IQ test

2016-12-02 20:32:29 UTC  

And P(B) = P(choose fair and get head) + P(choose bias and get head)

2016-12-02 20:32:49 UTC  

Which is 3/4

2016-12-02 20:33:05 UTC  

So 1/2 divided by 3/4 is 2/3

2016-12-02 20:33:33 UTC  

Probability of getting another head is 2/3

2016-12-02 20:34:45 UTC  

I have no idea of how that method works

2016-12-02 20:35:14 UTC  

all I did was exclude the first coin

2016-12-02 20:35:17 UTC  

Basically it's conditional probability

2016-12-02 20:35:22 UTC  

unless you're supposed to put it back in

2016-12-02 20:35:36 UTC  

What's the chance of getting the double head given that the first side was a head

2016-12-02 20:36:36 UTC  

A is the probability of getting the biased coin and B is the probability of getting a head from next flip

2016-12-02 20:37:16 UTC  

So P(A and B) is the probability of getting the biased coin and getting a head next

2016-12-02 20:37:36 UTC  

hey

2016-12-02 20:38:06 UTC  

hello and welcome @Chin what platform do you primarily play on?

2016-12-02 20:38:16 UTC  

PC/PS4