Message from @2Lazy2BeOriginal
Discord ID: 803322164215808010
oh my bad, Idk who did
Charles Babbage
Say Trump and you get an early summer vacation
thats smart
<:thinking:726878987837636698>
Hey I need help isolating t from the d =v0(t) 1/2(at^2)
Part of me thinks it’s the quadratic formula I should use but I want to make sure there’s other ways to isolate it before resorting to it
as in at^2 v0t -2d
no. isolate for t is via quadratic formula is the quickest way
so 1/2at^2 + v0t - d = 0 than use the quadratic formula?
I’m not sure if I’m doing it right but
the given weight is 11.8N btw
Do I need to the parallel gravity and add it to counter the applied force?
yup
it's on a ramp, so you'd need to breakdown the gravity force into x- and y-component
ok so right now I'm adding the Fg // + Ff + Fapp
my answer is 44.768m up. can ya'll see if I missed something since it's pretty steep
Fg-x?
i'm doing my hw rn so i might not be able to help you 🤣 see if omni calculator has a preset
Oh idk what to call the applied force for the hypotenuse since the box is gonna move at an angle
Idk if I was suppose to make all the components horizontal or something
split it into components
for find fg
then for x-component you have cos[angle] while y-component you have sin[angle]
Anyone mind helping me on my calc quiz
@Iamspeedhulkdab post the question
@Iamspeedhulkdab check ur dm
I know fg which is mg. I split it into fg parallel and fg perpendicular. Is there something else I should do?
no, i think that's it
ok so the normal force should be the opposite of fg perpendicular and than I can find the friction force at 56 degrees.
I then added up the applied, parallel, and friction force to get a net force of 14
all 3 of them are at a 56 degree angle so
the y-direction would be 0
but, yeah, that's pretty much it
ok my final answer is 44m up
idk if it's even right but
👍
I didn't watch the lesson so I'm taking a wild guess
any of yall know how to solve triangle similarty proofs?