this is the example i found

i supposed in this case we can solve for half of the equations 🤔

4 +/- i

I think the answer is just (x^2)-16-xi-4i

but that just doesnt look right for some reason

maybe? this is the first time i run into integrals

I took a course on complex polynomials but that was a while ago

@isoboto I feel kinda dumb because I learned all this stuff but when anyone asks about it the first thing I do is google it.

shhhhh dont tell anyone

<:KEK:795742276549607456> that's me in every class

okay so i found another example

basically this is just expanding stuff? 🤨

not sure how the "i" works hmmmm

yea

oh then it should be easy (i think XD)

"i" is actually an unreal number

It is the square root of negative one

hmm okay so when expanding it, we keep it until the end?

so basically i^2 = -1

what puzzled me is the "+4" they had

ah, okay

in the question the person was asking, -4 was by itself

yea

the zeros were

-4

and

4 + i

yea

Okay so this is my rough work

The i looks like it can be further simplified tho

algebra 2 help
Write a polynomial function of least degree w/integral coefficients that have the given zeroes (-4, 4+i)

except the first zero; -4

would be written

(x+4)

<:What2:777241822930010132> because the sign flip?

yea

man, why are we doing their homework for them anyways? lol

would that also applie to 4+i?

yes