Anyone understand PreCal?

Sure I took it last summer

First I divide by 5

Then set it up to look like (3x+3)ln(2)= ln(97/5)

<:Poggers:796912784473456640>

Math

Then 3x+3 = ln(97/5) / ln(2)

Then divide by 3: x + 1 = ln(97/5) / ln(2) / 3

And then what?

I would have subtracted 3 first

But if you go that way you would do this

Before dividing? That makes sense.

Anybody have a clue on how the hell to do this?

Exactly what I thought. But I checked it on an online calculator and it gave me this:

Gimme a sec

Alr. Thanks dude.

They’re the same thing

Basically you’re still subtracting one since 3ln2/3ln2 is one

Ohhhhhh

Thanks!!!!!!!

I owe you one. I have been stuck on that question for over 40 mins

I recommend that you get a TI nspire student software for precalc

There’s a free trial for 30 days on the website

@Porcupioneer

Holy crap

Im iffy on the last point, but otherwise i think i got a and b correct

Sorry about the bad handwriting 😅

Wow....

@Porcupioneer i forgot to break down 3kg into F-x and F-y. so Fg in the first step should be analyzed over with the angle 30 degree

but you get the general direction you can to

You're freaking awesome lol

dude that looks like the mona lisa compared to mine

not really 😂 it's the wrong solution/answer

But you told me how to fix it

good luck 👍 tell me the answer afterward when you received the solution key

I will