Message from @2Lazy2BeOriginal
Discord ID: 796943546334576640
Oh shit new channel Anyone wanna do my math homework š
what is it?
Lolol jk jk jk
oh I have this physics assignment and this bonus question
Just kidding, I just noticed we had this New channel š
I might know how to do this but I'll ask ya'll to compare answer. not a quiz just an assignment
Lol anyone taking calc here?
Iām lost man
no still in hs sorry
My Calc class had a 5% pass rate. <:KEK:795742276549607456>
I handed it in lol
I don't think I got it right since it was like 192m
I took calc, but i am not sure if canadian level is different from us level
I might have messed up with finding acceleration or something
It is a pretty easy question. Sorry i couldn't get to it earlier. Did you follow similar steps like i did? š
I put it as -7m/s/s
well I converted it to kg but don't know what you got for friction
you judge the force in the x-direction
since the puck is sliding on its own with no applied force, only friction is acting on it
I"m pretty sure the only force acting on it the friction and it's moving constantly so the final velocity should be 0
this is the steps I did
i quickly calculated it out. a-value is about -7.85 m/s2. so you should be good
looks right to me š
I was skeptic with the 192m but forgot it's a hockey stick
although i personally wouldn't find the time
it's an extra step that can mess up
oh I don't know how to find it without time
i'd use this equation:
I don't know how far it goes though
I assume x is distance
that's what you're finding
yes, x is the distance
the question asks for how far it will slide, no?
or could I isolate x and have it vi^2 - v^2 + 2a = x
v-final is just 0
wait, no vf^2-Vi^2/2a = x
idk if my algerbra is right but I think that's how it goes
he said I would learn it in grade 12 so
lmao yeah (vf^2 - v0^2) / 2a = x
it's simple algebra lmao. you just move the pieaces around