Message from @Tervy
Discord ID: 374932262208274442
was i supposed to solve the y2-y1 ove x2-x1?
cuz i did
and got -8/6
or -1 1/3
-1.3333333
easier if you dont transfer it to decimals
you are supposed to get -8/6 afaik
ok
ofc common factor 2 makes it -4/3
ok
swo now where do i go from here
then its justthen its just y=-4/3*X-C and we take your first numbers aka 5=-4/3*(-4)+C
and from that you can calculate the C by basic algrebra spinning
what is c exactly
like what is that variable for
its part of the line equation
i dont remenevbr ever learning that ugh
i think in english language the linear function uses Y=M*X+K
basically how far your line is moved from the centre
c means slope?
cuz m is slope
wait which C
i dont remmeber using c or k for anythiong
aka what we first calculated was M
and now you need to solve K (aka C in my example)
oh so the slope of the line is -4/3?
yes
oh oh oh
i got it now
i was confused
yeah my bad... i tend to forget that regional variations exist
okay so then we know what the slope of the line is just gotta get the line and write an equation for it basically
yeah and the equation is directly there if 5=-4/3*X-4+K
and you just spin the K to other side of the = sign
and rest is easy for you
so would it be 5-k on the other side of the equal sign?
yes and then you //-5 from whole equation to get K alone there
and simplify
also i just realised what your k is. is it our b? like in the slope formula y=mx+b is yours y=mx+k?
then add that "K" value to the Y=-4/3*X+K