Message from @Citizen Z
Discord ID: 527772890154926081
First, the angle between the top of the object and the bottom needs to be less than 0.02 degrees in order for it to be unresolvable
No it is .02 degrees
Second, objects disappear from view at a distance of three miles
I said objects 5 feet high disappear
That's fine
Equal or less than
A 6 foot man at 3 miles you would still see his head
Mmhmm
His legs and body would blend in with the horizon
Gibson_1952_The_perceived_slant_of_visual_surfaces--optical_and_geographical.pdf
Fair enough
Gibson_1952_The_perceived_slant_of_visual_surfaces--optical_and_geographical.pdf
This guy was a globe earther im pretty sure but knew how optics worked
Hold on bud I'm not finished yet
You have to debunk james gibson
So we would have something like this?
Not me
With 15840 feet equal to three miles
And the eye level of the observer at 6 ft
I dunno what you are trying to work out
Fine I'll change it
Observer 5 feet. 15000 feet..5 feet gone
Ok but this is the information that was given, yea?
Thats with 20/20 vision
🤔
The object would be gone from view at three miles away
We good so far?
Thats what it seems to be when tested at the beach
Ok I'll keep going then
At about 3 miles 5 foot objects are gone
K keep goin. Dont forget to read James gibson
Gnite
Ok just a sec I'm doing the math
Tired nite
This is what the angle would be using the height of the observer and the distance of three miles
Which part ?
1 inch off the ground or 5 feet up?
6 feet?