I input T, P and dT/dh only goes up to that value on the simulation, where it is following the earth curve

Which gives us this result

@Logrian doesn't it have to do with the height of the object too

Which should be sufficient

an even if we go to 56 ft observer height we dont get ten miles Cata.

@Logrian not observer height

horizon doesnt have a height

How did you measure the distance to the horizon?

by knowing the distance beyond the towers an the observer hight, according to the glob model the MAX horizon is 1.22miles

Refraction shifts the position of the horizon away from the geometric horizon

@Logrian isn't the calculator based on the globe model

no, its basic geometry tangent

with the glob model R

Of a sphere the size of earth

pit, that silly

Pray why?

If someone disproves you. You should try to disprove them not call them silly

@Question For Your Life I'm honestly only aware of Refraction as the concept, not different types

Ice = positive T gradient ergo refraction around the curve.

Also your refraction is assuming an R value which doesnt exist in reality, thats wht its a model, an idea 😉

Seems to fit your obervation pretty well to me 🤔

Nope, you dont get 7 miles of refraction 😉

an also you cannot have refraction, unless youre a flat earther

Only in your mind

facts

your glob model needs a PHYSICAL horizon

Refraction happens perfectly well regardless of the shape of the earth

which is why ships disappear

according to you the glob model has a physical horizon

this is determined by R

this is NOT observed

ergo no R no ball

No. You dot understand the effect refraction has on the apparent position of the physical horizon...

we do, this is the problem