the irony

"over 20 miles high, horizon still flat"

you can read! excellent 🙂

progress 💪

Should it be curving significantly at 20 miles high?

"3959-(3959*(COS(ASIN(L/3959))))" who wrote this equation lmao

we can't measure ANY curvature. anywhere. either land, sea or air

What's the ASIN for?

@Flat Earth PhD but should you be measuring curvature?

LMAO

what?!?!

why wouldn't we?!?!?

Maybe the curvature is too little to measure at low altitudes?

Do you know how much curvature you should be measuring?

yes! it's above in that chart!!

8 inches per mile squared

at least for the first few hundred miles

That does not tell you how much the HORIZON should curve, I'm talking about whether it looks flat or not

we aren't measuring that as proof. it's too difficult

Then what's the point of an image saying the horizon looks flat?

You can't measure 8 inches per mile² looking at the horizon

I was addressing the point someone above made about shouldn't you be able to see the curvature

stop trolling

last warning

?

"but I'm not trolling"

Sure, go with that, anyway do you know why this chart uses ASIN(L/R)?

spherical geometry

Ok so the answer is because it's measuring straight line distance, not curved line distance, (it's also measuring normal to LOS drop, not drop normal to surface drop) which is not what it should be using for exact results

You could remove the ASIN and the equation would be perfectly valid

Assuming you're using radians

And it would be more accurate

then tell us what numbers you get for Earth's curvature.

You could then divide the entire equation by cos(theta) to get normal to surface drop

and we will see how it compares to what we measure

which is 0

Who talked about measuring?

I'm just talking about the equation

I'm not talking about how it compares to results

I'm not here to fight for the globe Earth