You have the density so solve for n by raising the density (d) to the third power

And you have d^3=3/4(pi)n

After that it should be easy to solve for n

Then multiply d^3 by n for n*d^3=3/4(pi)

And then divide by (d^3)

for n = 3/(4(pi)d^3)

so if d= 10

then n =3/(4(10^3)*(pi)))

so it is 3/(4000*(pi))

is the square root still underneath the pi?

in that step

There is no square root, in that step it is 10 (d) raised to the third power

Unless I read that wrong, it is a 1/3 as the power right?

oh wow, lol there is no square root, i was thinking the fraction

Lol

Yeah all of the numbers are under the 3

.........3
=========
4(10^3)(pi)

okay got it, thanks

the rest is graphing stuff and I got that stuff down it was that question that was giving me beef

Aight cool beans

I don't have to do that question on the test but we have to know it

Is there something within those topics that grinds your gears? Surely there has to be something...

huh im in algebra 2

I learned logarithms in algebra 2 also. I was introduced to them in algebra 1 but only started working with them much in algebra 2.

huh ok because I feel really out of my league lol

That is usually a good thing.

You're ahead of the game

No. There’s really nothing.

Hmm, you might just have to invent a problem and bullshit the essay. Dunno what else to think of myself

I’m looking at going into law, so I’m just going to use that.

Problem solved then

me too nice

help i dont know how to create a table with a quadratic equation

I figured it out

?

Kinda

i know the constant is the 0 value

but i dont know how to create it on both the axis

Just plug in the numbers from the x column into the equation.

so it would just be

f(-1)=-1^2-2(-1)-8?