Message from @Paragram Slide - AZ

Discord ID: 496410306872999936


2018-09-28 20:56:53 UTC  

it must be the size then

2018-09-28 20:57:11 UTC  

get(this.size - 1) is returning null

2018-09-28 20:58:54 UTC  

```
ListNode last = get(this.size - 1);
if (last != null) {
last.next = newNode;
++this.size;
return true;
}
return false;
```

2018-09-28 20:59:42 UTC  

thanks

2018-09-28 21:02:13 UTC  

this would only happen adding first node to list I would think

2018-09-28 21:02:18 UTC  

what is this class?

2018-09-28 21:02:22 UTC  

data structures?

2018-09-28 21:02:27 UTC  

or Java class?

2018-09-28 21:03:39 UTC  

Data Structures

2018-09-28 21:04:23 UTC  

I actually have a Java developer certificate but it was a long time ago so I have to relearn everything

2018-09-28 21:04:36 UTC  

Got it same time as I graduated high school

2018-09-28 21:04:38 UTC  

when I took that class we used C

2018-09-28 21:04:56 UTC  

1999 😉

2018-09-28 21:05:47 UTC  

Java was its own class back then - the OOP class

2018-09-28 21:13:02 UTC  

I had to take a 3 part Java series to get into this class

2018-09-28 21:13:10 UTC  

It was part of my certificate

2018-09-28 21:24:09 UTC  

nice

2018-09-28 21:24:20 UTC  

it's a good line of work

2018-10-01 19:56:08 UTC  

I need help factoring a math problem @here

2018-10-01 19:56:30 UTC  

-x^2 + 5x + 14

2018-10-01 19:57:20 UTC  

(-x - 2)(x - 7)

2018-10-01 19:57:37 UTC  

I have meeting in 3 mins

2018-10-01 19:57:47 UTC  

but that is close

2018-10-01 19:59:26 UTC  

@Warren H What class is that for?

2018-10-01 20:00:26 UTC  

Have you been taught any particular methods for factoring?

2018-10-01 20:01:53 UTC  

@Jacob it's for college learning support math

2018-10-01 20:02:29 UTC  

Not really all I've learned is the "what adds to give us the middle term and multiplies to give us the third term

2018-10-01 20:03:28 UTC  

Okay, well first try writing out this (-x )(x ), think of a few number that multiply to form 14, and see which of those can be added or subtracted to form 5

2018-10-01 20:04:51 UTC  

In this case, 7*2 is 14, and 7-2 is 5. So, you put the 7 and the 2 in those parentheses and change the signs as needed.

2018-10-01 20:05:44 UTC  

Okay

2018-10-01 20:06:43 UTC  

(-x + 7)(x - 2) would create a negative 14, so, although that would work for the 5x, it wouldn't work for the 14. So the right answer is the one Paradigm Slide gave.

2018-10-01 20:06:59 UTC  

Honestly, this is largely just process of elimination, unless someone knows a better way

2018-10-01 20:07:40 UTC  

So before that wouldnt you write it as
-x^2+7x-2x+14? Factor out the -x, but then what happens to the x attached to the 7 and 2?

2018-10-01 20:08:29 UTC  

-x(-x+7)(x-2)(x+14) ?

2018-10-01 20:31:56 UTC  

It would be written out as -x^2-2x+7x-14

2018-10-01 22:58:49 UTC  

@Warren H so if you have (-x-a)(x-b) for some a,b then a*b = 14 and b-a = 5. The solution from inspection is a = 2 and b=7.

2018-10-01 23:31:00 UTC  

@ThisIsChris i imagined completing the square to be something different. iirc completeing the square is transforming a quadratic into the form (ax+b)^2+c

2018-10-01 23:33:39 UTC  

@YourFundamentalTheorum you're right my bad

2018-10-10 14:46:50 UTC  

If any of you nibbas need help with Econ or Statistics Im your guy.

2018-10-10 14:47:17 UTC  

Or business stuff in general.

2018-10-10 18:30:41 UTC  

@Sam Anderson <@&387091385075105804> role'd