Message from YourFundamentalTheorum in MacGuyver - Skills & Academics #stem
there still is work though, just not boom levels
Is it $120k a year like it was a decade ago?
I'm not considering it, just wondering. I know a lot of guys who made ridiculous money back then
newer engineers aren't making that anymore, senior engineers can make 200-300k still.
my friends who did get oil engineering jobs are making 55 - 75k similar to other engineering fields just out of college
I'm talking roughnecks
Oh, yea close to above number now
Happy Pi Day!
Any of you goys into data mining? I've been fiddling around with R a lot recently.
@ThisIsChris Yeah I structure a lot of unstructured data on the web for economic system research mostly.
Been getting into data science comprehensively lately, I feel like the field is about to blow up.
@Attrition in the desert definitely! What data is it that you are making available and to who?
@ThisIsChris Mostly data on commerce exchanges in SE asia. The place I'm working at now handles a lot of soft/hard currency transactions.
That's neat. I wonder if it's simultaneously done in all areas of the animal.
Hey guys, I'm Nick, and I'm a ChemE undergraduate from NY, excited to talk with all of you
@Nicholas1166 - NY sorry, role'd not roll'd. I gave you the @`AE` role (academic expert) so you will be alerted when people ping @`AE` with academic questions you may be able to help with.
Ah, OK. Yeah, I'd be glad to lend a hand if I can, although I am just a junior right now
I'm graduated from a university with a degree in math
ask me math questions
if you need halp
I very well might, math is my weakest subject. Thank you for the offer.
I didn't know this sever had a role thing. Can I get a role and be alerted?
@ThisIsChris hey do you have any good explanation on how to find isomorphisms between two polynomial factor groups?
that is an isomorphism phi: F[x]/f1(x) -> F[x]/f2(x) where F[x] is the field of polynomials with coefficients in Z_q and f1(x) and f2(x) are irreducible polynomials in F[x]
@YourFundamentalTheorum by F[x]/f1(x) do you mean a quotient group? If so, what is the group you are doing F[x] modulo with? f1 doesn't generate a group unless I am missing something
and F[x] is a field of polynomials in x with coefficients in Z_q
@YourFundamentalTheorum thanks. How about for an element of F[x]/f1 called G, take a representative g, phi(G) = the coset of g*f2/f1 . Need to prove that the coset is independent of the choice of representative g
the last part is a given.
On the right hand side I mean g times f2 divided by f1 in the normal sense for poly nomials
F[x]/f1(x) is usually represented by all the polynomials """"less than""""" f1(x)
a lesser degree than f1(x) that is