Message from micbwilli in MacGuyver - Skills & Academics #stem

2018-03-07 20:09:18 UTC  

It's possible to walk onto a rig as a roughneck and elevate yourself to company man position if you are very competant, adverse to high stress, can pick up technical drilling intuition, and are ok with very little social life that comes with living in remote areas and a disproportionately male population. If you can handle all that there is good money to be made.

2018-03-07 20:27:23 UTC  

@Brandon Ironside- ND Have you worked in the oil industry? I was under the impression the boom was dead

2018-03-07 20:32:29 UTC  

@John O - only as an intern for a brief period. The boom is dead for now with the current oil prices. I choose to take my career into a different engineering direction after what little exposure I did have right out of college.

2018-03-07 20:33:14 UTC  

there still is work though, just not boom levels

2018-03-07 20:33:47 UTC  

Is it $120k a year like it was a decade ago?

2018-03-07 20:34:34 UTC  

I'm not considering it, just wondering. I know a lot of guys who made ridiculous money back then

2018-03-07 20:41:59 UTC  

newer engineers aren't making that anymore, senior engineers can make 200-300k still.

2018-03-07 20:43:35 UTC  

my friends who did get oil engineering jobs are making 55 - 75k similar to other engineering fields just out of college

2018-03-07 20:47:36 UTC  

I'm talking roughnecks

2018-03-07 21:01:06 UTC  


2018-03-07 21:32:38 UTC  

Oh, yea close to above number now

2018-03-07 22:33:47 UTC  

That sucks.

2018-03-14 04:31:16 UTC  

Happy Pi Day!

2018-07-09 04:58:36 UTC  

Any of you goys into data mining? I've been fiddling around with R a lot recently.

2018-07-09 12:20:09 UTC  
2018-07-09 18:20:48 UTC  

@ThisIsChris Yeah I structure a lot of unstructured data on the web for economic system research mostly.

2018-07-09 18:21:37 UTC  

Been getting into data science comprehensively lately, I feel like the field is about to blow up.

2018-07-10 12:13:39 UTC  

@Attrition in the desert definitely! What data is it that you are making available and to who?

2018-07-10 16:27:33 UTC  

@ThisIsChris Mostly data on commerce exchanges in SE asia. The place I'm working at now handles a lot of soft/hard currency transactions.

2018-09-18 01:54:12 UTC  

That's neat. I wonder if it's simultaneously done in all areas of the animal.

2018-09-23 19:03:48 UTC  

Hey guys, I'm Nick, and I'm a ChemE undergraduate from NY, excited to talk with all of you

2018-09-23 19:11:58 UTC  


2018-09-23 19:12:00 UTC  


2018-09-24 01:38:13 UTC  
2018-09-24 02:36:03 UTC  


2018-09-24 03:21:31 UTC  

@Nicholas1166 - NY sorry, role'd not roll'd. I gave you the @`AE` role (academic expert) so you will be alerted when people ping @`AE` with academic questions you may be able to help with.

2018-09-24 03:37:27 UTC  

Ah, OK. Yeah, I'd be glad to lend a hand if I can, although I am just a junior right now

2018-09-24 04:23:03 UTC  

I'm graduated from a university with a degree in math

2018-09-24 04:23:05 UTC  

ask me math questions

2018-09-24 04:23:09 UTC  

if you need halp

2018-09-24 04:31:53 UTC  

I very well might, math is my weakest subject. Thank you for the offer.

2018-10-03 05:19:28 UTC  

I didn't know this sever had a role thing. Can I get a role and be alerted?

2018-10-03 16:45:13 UTC  
2018-10-22 06:55:35 UTC  

@ThisIsChris hey do you have any good explanation on how to find isomorphisms between two polynomial factor groups?

2018-10-22 06:56:33 UTC  

that is an isomorphism phi: F[x]/f1(x) -> F[x]/f2(x) where F[x] is the field of polynomials with coefficients in Z_q and f1(x) and f2(x) are irreducible polynomials in F[x]

2018-10-22 07:18:25 UTC  

@YourFundamentalTheorum by F[x]/f1(x) do you mean a quotient group? If so, what is the group you are doing F[x] modulo with? f1 doesn't generate a group unless I am missing something

2018-10-22 07:18:42 UTC  

@ThisIsChris quotient field

2018-10-22 07:19:06 UTC  

and F[x] is a field of polynomials in x with coefficients in Z_q

2018-10-22 07:24:17 UTC  

@YourFundamentalTheorum thanks. How about for an element of F[x]/f1 called G, take a representative g, phi(G) = the coset of g*f2/f1 . Need to prove that the coset is independent of the choice of representative g

2018-10-22 07:26:20 UTC  

the last part is a given.