Spencer is irrelevant. Eli wanted IE to be an RS centered group.

@Reinhard Wolff are Cowboy boots appropriate attire for the conference next year?

@NateDahl76 >assuming any of these aliases are real

@NateDahl76 he made that alias to avoid detection of his account

@Volkmom hahahaha we are timeless. . Ageless !

I don't like to be a hater but Operation Homeland is an awful name

thats right! @The Morrígan

Ah okay friends thanks

If f(x) = x^3 + x^2 + x + c, then find f"(x). 3x^2 + 2x + 1 + 0 -> 6x + 2 +0

The struggle will reveal the king, not the other way around

this is the best black metal album I've heard in a few years

https://www.youtube.com/watch?v=m_SK1Gn63f0

@ThisIsChris You failed.

Awww you ladies are gems! @Volkmom @The Morrígan

hey guys i have to run ttyl

Richard Spencer was narcissistically wounded by the refusal of @Reinhard Wolff to become his underling.

Because Richard wanted us to be his body guards and stuff.

🤔

@Patrick Casey has anyone proposed the idea of a public speaking official server for training our rhetorical skills?

@Rabbidsith whoops 😆

@celticflame we ladies are now all ageless !

@ThisIsChris ;)

@Redbird3000 You didn't tag him in that, friend @Reinhard Wolff ^^^

And then TWP did his bidding, in addition to Heimbach's insatiable trailer lust

Yes we are!! @The Morrígan

My channel
https://youtu.be/eWoS7--Lvm4

Back when Reinhard Wolff was a name that put the fear in people's hearts

Richard wanted us to fight Antifa with him, and he was forced to turn to Heimbach.

@GingerRose99 Subbed.

Oh cool! @GingerRose99

@Rabbidsith btw the answer to my question before was f(x) = a\*sin(x) + b\*cos(x) for any constants a and b

@Redbird3000 Literature server could be used for this. Message @CarletonJ

@NateDahl76 yeah I'm having trouble with figuring this tagging thing out

@Rabbidsith
Thankyou

Reinhard Wolff is much more intimidating than Paddy Casey

Subbed! @GingerRose99

Paddy C baby

I used to be afraid of the name Reinhard Wolff, what a name

"AIPAC is Gay" Never forget.

@ThisIsChris f"(x) + f(x) = 0. f(x) = asin(x) + bcos(x)?

for all constants a and b?

@Rabbidsith yes