p!check'em

3828133389
Faggot.

p!check'em

6343864539
Faggot.

p!check'em

3571497461
Faggot.

p!check'em

p!check'em

p!check'em

p!check'em

DONT SPAM THE GENERAL PLEASE

p!check'em If trips, we crowdfund a helicopter

also bots run on a max bandwidth

wowruip

Rip bot.

RIP

it'll catch up

it's just you triggered it

Still though, don't spam general.

9217917886
Faggot.

8269507627
Faggot.

6679708583
Faggot.

8250162165
Faggot.

8090911906
Faggot.

That's a lot of Faggots

p!check'em if gets, then we listen to @Verm

What are you using to generate the numbers though

basically darty I take the log10 of whatever size I want
then roll a number for each space
if that number is the same as the prior it'll add +1 to how many are repeating
and then it adds the number to the front of the string

http://i.imgur.com/GEKzxEI.jpg

9423524859
Faggot.

> makes a bot to generate imageboard style post numbers
> numbers are completely randomized and are not actually post numbers

so you start out with say 1
then roll a 1
1 == 1 is true, so repeating is 2
and then 11 is the string
then you roll a 2
2 isn't the same as 1, so repeating is locked at 2
and then you get 211

Why not just generate a random number between 1000000 and 9999999?

the individual numbers are just (int)(Math.Random()*10)

and because then to check how many repeating I'd need to do a looot more modulus logic

same amount of work this just came into my head first

same accuracy too

http://i.imgur.com/gyYauc5.jpg

int rep(int digits)
{
if(digits%10==(digits/10)%10)
{
return reps(digits/10)+1;
}
return 0;
}

that would only check 2 digits out of the list and you'd need to cut off the ones before it

its recursive.