Message from @jeremy

Discord ID: 569228151507648524


2019-04-20 18:21:33 UTC  

thats what we are on

2019-04-20 18:21:50 UTC  

needs to work for more than 100 miles lol

2019-04-20 18:22:05 UTC  

Yeah, but it is rounded, and that slight difference adds up over long distances

2019-04-20 18:22:17 UTC  

7.98 is a more precise figure

2019-04-20 18:23:06 UTC  

whats the formula that works for 24,000 miles

2019-04-20 18:23:11 UTC  

And if you wanted to get even more precise, there is the slight oblate shape of the earth

2019-04-20 18:23:22 UTC  

But approximations are fine

2019-04-20 18:23:23 UTC  

yeah i know its pear shaped now

2019-04-20 18:23:57 UTC  

but i think we should know the formula that works for a whole sphere

2019-04-20 18:24:34 UTC  

It depends on what you are trying to find

2019-04-20 18:24:44 UTC  

the amount of curve

2019-04-20 18:25:26 UTC  

1 mile out 8 inches 2 miles out is what? whats the real formula

2019-04-20 18:25:57 UTC  

need something that works with more than 100 miles

2019-04-20 18:26:42 UTC  

do u know what the real formula is ?

2019-04-20 18:27:54 UTC  

You could calculate it with the pythagorean theorem, but 7.98 inches per mile squared works fine. You square the mile because it is curved.

2019-04-20 18:27:55 UTC  

people are claiming we see too far so im trying to figure out the amount of curve er mile but 8 inches squared is clearly not correct

2019-04-20 18:28:15 UTC  

but it only works for 100 feet

2019-04-20 18:28:19 UTC  

sorry 100 miles

2019-04-20 18:28:30 UTC  

i need something that works with a whole sphere

2019-04-20 18:28:49 UTC  

or 24,000 miles

2019-04-20 18:29:27 UTC  

we arent on a 100 mile big sphere

2019-04-20 18:30:52 UTC  

Well, let's see.
8 inches*100^2= 80,000
7.98 inches*100^2= 79,800
200 inch difference after 100 miles. Because rounding

2019-04-20 18:31:29 UTC  

It is calculated from an approximately 25,000 mile circumference sphere

2019-04-20 18:32:44 UTC  

so 7.98 inches per mile squared wotks for a full sphere?

2019-04-20 18:32:48 UTC  

works

2019-04-20 18:33:21 UTC  

A sphere with a radius of 3,963 miles

2019-04-20 18:33:57 UTC  

im gonna have to research this

2019-04-20 18:34:49 UTC  

It assumes earth is a perfect sphere, but for general purposes, that assumption works even considering the model states it as slightly oblate

2019-04-20 18:34:59 UTC  

because did u see the thing i said earlier about man a man b and man c all in a straight line 1 mile apart?

2019-04-20 18:36:24 UTC  

man a to man b 8 inches of drop then from man b to man c 8 inches of drop but from a to c is 32 inches of drop that doesnt seem possible where did the extra amount of earth come from to drop

2019-04-20 18:36:59 UTC  

sorry im not great with math but reality i can handle fairly well

2019-04-20 18:37:31 UTC  

From the curvature.
If it was 16 inches from a to c instead of 32, it wouldn't be curve. Instead, it would be like you are on a cone, a straight line slope.

2019-04-20 18:38:04 UTC  

i understand why the math needs to work but in reality where did the extra earth come from somehow

2019-04-20 18:38:19 UTC  

from a to b its 8 inches right

2019-04-20 18:38:27 UTC  

and b to c is 8 inches

2019-04-20 18:39:09 UTC  

ur telling me that would never make a circle ?

2019-04-20 18:41:04 UTC  

Yes, 8 inches of drop over one mile, but a curve would have it drop away exponentially or else it would be a straight line. So, a to b, 8 inches of drop, b to c, 8 inches, a to c, 32 inches. You are thinking about this in terms of slopes on a coordinate plane, that doesn't apply here. This is a curved surface we are talking about

2019-04-20 18:41:47 UTC  

i tink i would be able to graph both of the formulas out to be a circle or straight line

2019-04-20 18:42:16 UTC  

idk like i said im gonna have to look into this more

2019-04-20 18:42:47 UTC  

It might be easier to see this in a picture rather than in words

2019-04-20 18:43:19 UTC  

well first im gonna see if i can graph out both formulas to be a straight line